Clocks & calendars

RoadmapsAptitude

Mental model

Clocks are circular speed tracks; calendars are infinite lines sliced into repeating blocks of 7 days.

For clocks, map both hands to angular displacement to find their relative distance. For calendars, compress massive timeframes by taking the remainder of days divided by 7 (Odd Days).

Method

  1. First, classify the problem: does it ask for a Clock angle/time or a Calendar day of the week?
  2. For Clocks: Treat the clock face as 360 degrees. Convert the time to Hours (H) and Minutes (M).
  3. Apply the relative speed formula: Angle = |30H - 5.5M|. If the result is greater than 180, subtract it from 360 to get the inner angle.
  4. For Calendars: Use the 'Odd Days' modulo method. Remember an ordinary year has 1 odd day, and a leap year has 2 odd days.
  5. Calculate total odd days from the reference date to the target date by summing the odd days for all completed years and months, then find the remainder when divided by 7 to determine the weekday.

Worked example

Problem: What is the angle between the hour and minute hand of a clock exactly at 3:15?

  1. Classify problem: This is a Clock angle problem.
  2. Identify the variables from the time given: H = 3, M = 15.
  3. Apply the relative angle formula: Angle = |30H - 5.5M|.
  4. Substitute the values: |30(3) - 5.5(15)|.
  5. Calculate the components: 90 - 82.5.
  6. Find the absolute difference: |7.5| = 7.5 degrees.

Answer: 7.5 degrees

Common mistakes

Glossary

displacement
The distance an object, like a clock hand, has moved from its starting position.
century
A period of 100 years, like the year 1900 or 2000.
modulo
A math operation that finds the remainder after dividing, often used to count repeating days.

Recall questions

Questions & answers

Today is Monday. After 61 days, it will be:

Saturday

Approach: Find odd days: 61 divided by 7 leaves a remainder of 5. Add 5 days to Monday -> Saturday.

At what angle are the hands of a clock inclined at 15 minutes past 5?

67.5 degrees

Approach: H=5, M=15. Angle = |30(5) - 5.5(15)| = |150 - 82.5| = 67.5 degrees.

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