Calculate heat generated by current

RoadmapsPhysics (Class 10)

Scenario

Phone ko lagatar charge karne par wo garam kyu ho jata hai?

Current guzarne par heat paida hoti hai. Ye heat kitni hogi, iska formula kya hai?

Mental model

Electric friction heat paida karta hai.

Jab electrons wire (resistor) mein bhaagte hain, toh wo atoms se takrate hain. Is takkar (resistance) ki wajah se kinetic energy heat mein badal jati hai.

Explanation

Is process ko heating effect of electric current kehte hain. Iska mathematically study James Prescott Joule ne kiya tha.

Joule's law of heating kehta hai ki heat paida hona (`H`) teen cheezon par depend karta hai: Current ka square (`I^2`), Resistance (`R`), aur Time (`t`) jiske liye current baha.

Formula hai `H = I^2 * R * t`. Heat ek tarah ki energy hai, isliye iski SI unit Joule (`J`) hoti hai. Formula use karte waqt time humesha seconds mein hona chahiye.

Ye effect humare liye nuksaan-dayak bhi hai (phone ka garam hona) aur faydemand bhi. Electric heater, iron, toaster, aur bulb sab is principle par kaam karte hain. Electric fuse bhi isi wajah se melt hokar circuit todta hai jab current limit se zyada badh jaye.

Worked example

Problem: `100 J` of heat is produced each second in a `4 ohm` resistance. Find the potential difference across the resistor.

  1. Given values likhte hain.
  2. Joule's law `H = I^2 R t` se current nikalte hain.
  3. Phir Ohm's law `V = IR` lagakar voltage nikalte hain.

Answer: 20 V

Problem: Compute the heat generated while transferring `96000 coulomb` of charge in one hour through a potential difference of `50 V`.

  1. Pehle time ko seconds mein convert karte hain.
  2. Current `I = Q/t` use karke nikalte hain.
  3. Ohm's law `R = V/I` se resistance nikalte hain.
  4. `H = V I t` ka bhi sidha istemaal kar sakte hain, jo aur asaan hai (`H = W = VQ`).

Answer: 4.8 * 10^6 J

Key points

Common mistakes

Recall questions

Questions & answers

Why does the cord of an electric heater not glow while the heating element does?

The heating element has very high resistance, so it produces a lot of heat (H = I^2Rt) and glows. The cord has low resistance (copper), so it produces negligible heat.

Approach: Compare their resistances using Joule's law.

100 J of heat is produced each second in a 4Ω resistance. Find the potential difference across the resistor.

20 V

Approach: H = V²t/R => 100 = V²(1)/4 => V² = 400 => V = 20 V.

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